How do you graph #y=sec(x-pi/4)#?

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Answer 1 · 2018-03-12T01:39:59

As below.

#y = asec(bx-c)+d# is the standard form.

#y = sec(x - pi/4)#

Amplitude #a = # none.

Period #= (2pi)/|b| = (2pi) / 1 = 2pi#

Phase shift #= -c / b =( (pi)/4) / 1 = pi / 4# #color(white)(aaa)(pi/4)# to the right.

#Vertical shift # = d = 0#

graph{sec(x - pi/4) [-10, 10, -5, 5]}