How do you graph #y= \sin 2\pi ( x + 2) + 4#?

1 Answer
Feb 8, 2018

The horizontal line through #(0,4)#

Explanation:

#y =sin2pi(x+2)+4#

Remember: #sinnpi =0 forall n in ZZ#

Hence, #sin2pi =0#

So, our function becomes:

#y =0(x+2)+4 =4#

Which is the horizontal line through #(0,4)#, shown below.

graph{sin(2pi)(x+2)+4 [-14.24, 14.24, -7.12, 7.12]}