How do you graph # y=sin(5/3x)#?

1 Answer
May 2, 2018

Answer:

As below.

Explanation:

Standard form is # y = A sin (Bx - C) + D#

#Given : " y = sin ((5/3) x#

#'Aplitude " = |A| = 1#

#"Period " = p = (2pi) / |B| = (2pi) / (5/3) = (6pi)/3#

#"Phase Shift " = - C / B = 0#

#"Vertical Shift " = D = 0#

graph{sin ((5/3)x) [-10, 10, -5, 5]}