How do you graph y=sin(5/3x)y=sin(53x)?

1 Answer
May 2, 2018

As below.

Explanation:

Standard form is y = A sin (Bx - C) + Dy=Asin(BxC)+D

Given : " y = sin ((5/3) xGiven:y=sin((53)x

'Aplitude " = |A| = 1

"Period " = p = (2pi) / |B| = (2pi) / (5/3) = (6pi)/3

"Phase Shift " = - C / B = 0

"Vertical Shift " = D = 0

graph{sin ((5/3)x) [-10, 10, -5, 5]}