How do you graph # y=sin(x-pi/2)#?

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Sep 14, 2016

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graph{-cosx [-2.916, 7.084, -2.38, 2.62]}

Explanation:

#y=sin(x-pi/2)#

#y=sin-(pi/2-x)#

As #sin(-theta)=-sintheta#,

#y=-sin(pi/2-x)=-cosx#

So plot #y=-cosx#

graph{-cosx [-2.916, 7.084, -2.38, 2.62]}

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