How do you graph #y=-sqrt(x)+1#?

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Answer 1 · 2017-06-01T18:44:42

See below

Let's plug in a few points for #x# and compute #y# and plot them.

#(0,1)#
#(1,0)#
#(4,-1)#
#(9,-2)#

graph{-sqrt(x) + 1 [-10, 10, -5, 5]}

If you look at the graph of the parent function:

#y=sqrt(x)#

graph{sqrt(x) [-10, 10, -5, 5]}

You'll notice that our graph is simply reflected about the x-axis because of the negative sign and shifted up by 1 unit because of the positive 1.