Question

How do you graph `y= (x-12)^2 -7`?

Answer 1

Simplify the function
y = `x^2 - 24x +137`

Find its vertex

x = `(-b)/(2a) = 24/2`= 12

Take a few points on both sides of 12

x : y
9 : 2
10 : -3
11 : -6
12 : -7
13 : -6
14 : -3
15 : 2
16 : 9

Polt the points and join them with a smooth line
graph{x^2-24x+137 [-20.27, 20.29, -10.14, 10.13]}