Question

How do you graph `y=x+12` and `y=1/4x-3`?

Answer 1

See below:

Explanation:

Each of these equations is a line. Let's do them one at a time, then combine them.

`y=x+12`

For this, we can draw a line with the `y`-intercept at 12 `(0,12)` and then with the slope being 1, we can also draw in a point at `(0+1, 12+1)=>(1,13)`, connect the dots and draw the line.

graph{x+12 [-20.58, 7.9, -0.82, 13.42]}

`y=1/4x-3`

We can graph the `y`-intercept point `(0,-3)` and with slope `1/4` we can also graph `(0+4, -3+1)=>(4,-2)`, connect them up and draw the line.

graph{1/4x-3 [-7.77, 24.27, -7.41, 8.61]}

Put them together and we have:

graph{(y-(x+12))(y-(1/4x-3))=0 [-24.43, 4.04, -12.2, 2.04]}