# How do you graph y = (x - 2)^2 + 1?

Aug 10, 2018

Refer Explanation

#### Explanation:

Given -

$y = {\left(x - 2\right)}^{2} + 1$

The equation is in the form $y = \left(x - h\right) + k$, then the vertex $\left(h , k\right)$.

In the given equation the vertex is $\left(2 , 1\right)$

Its y-intercept.

At x=0; y=(0-2)^2+1=4+1=5

y-intercept $\left(0 , 5\right)$

Its y - intercept $\left(0 , 5\right)$is above the vertex$\left(2 , 1\right)$ the curve opens up. Hence it has no x-intercept.