How do you graph #y = -x^2 + 3#?

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Answer 1 · 2017-02-16T14:32:48

find the two intercepts and join them up

y = #-x^2 + 3#

y intercept is 3

when y is 0 x is x intercept:

0 = #-x^2 + 3#

#x^2# = 3

#sqrt3# = x intercept; then you just connect them and you have your line.

Hopefully this was useful...