# How do you graph #y < x^2 + 4x#?

##### 1 Answer

Jun 15, 2017

First consider the equation

Note that this has zeros when

The vertex of this parabola will be halfway between the zeros, at

So, we can easily draw the parabola with the points

graph{x^2+4x [-14.09, 8.41, -5.855, 5.395]}

We want to find when

graph{y < x^2+4x [-14.09, 8.41, -5.855, 5.395]}