How do you graph # y= x^2+5 #?

1 Answer
mizoo
Mar 3, 2018

The graph looks like this
graph{x^2 + 5 [-14.1, 14.37, -1.99, 12.25]}

Explanation:

#y = x^2 + 0x + 5#, compared with the general form of parabola function #ax^2 + bx + c, a = 1, b = 0, c = 5#
It is a U shaped a parabola as a > 0.

x vertex:# = -b/(2a) =(-0)/2 = 0#
y #= 0 + 5 = 5#
#"Vertex": (0, 5)#

Two points:
#x = 1# : #y = 1^2 + 5 = 6 => (1, 6)#
# x = -1# : #y = (-1)^2 + 5 = 6 => (-1, 6)#

Find the three points and the graph looks like this https://www.desmos.com/calculator/qwjal4zmxo

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