How do you graph #y=x^2+8-3x#?
Here's one way: complete the square to find its vertex, then calculate a few more points by plugging in values of
Let's rearrange the equation:
This equation can't be factored, so let's complete the square:
This is the equation in vertex form:
We know the vertex is
The leading coefficient
We can get a few more points of the parabola by plugging in some values of
Graph and connect these points. Be sure to label the equation of the graph, label the axes, and include arrowheads.