# How do you graph #y=(x-5)^2#?

##### 1 Answer

Jul 17, 2015

This is a vertical parabola - sort of U shaped - with vertex at

#### Explanation:

The vertex is at the minimum value of the function.

Hence the vertex is at

The axis is vertical, passing through the vertex, so its equation is

The intercept with the

So the intercept is at

graph{(x-5)^2 [-39.58, 40.42, -5.28, 34.72]}