How do you graph #y=x-5#?

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Answer 1 · 2018-03-07T09:13:33

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For #x = 0#

#y = 0 - 5#

#y = -5# or #(0, -5)#

Second Point: For #x = 5#

#y = 5 - 5#

#y = 0# or #(5, 0)#

We can next plot the two points on the coordinate plane:

graph{(x^2+(y+5)^2-0.075)((x-5)^2+y^2-0.075)=0 [-14, 14, -7, 7]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y-x+5)(x^2+(y+5)^2-0.075)((x-5)^2+y^2-0.075)=0 [-14, 14, -7, 7]}