# How do you identify all asymptotes or holes for #y=(2x+1)-3/(x-4)#?

##### 1 Answer

Nov 1, 2016

#### Answer:

There are 2 asymptotes,

a vertical one

and a slant one

#### Explanation:

A vertical asymptote is

The slant asymptote is

graph{(y-2x-1-3/(x-4))(y-2x-1)=0 [-14.24, 14.23, -7.12, 7.12]}