# How do you identify all asymptotes or holes for y=(2x+1)-3/(x-4)?

Nov 1, 2016

a vertical one $x = 4$
and a slant one $y = 2 x + 1$
A vertical asymptote is $x = 4$ because we cannot divide by $0$
The slant asymptote is $y = 2 x + 1$