Question

How do you identify all asymptotes or holes for `y=(2x+1)-3/(x-4)`?

Answer 1

There are 2 asymptotes,
a vertical one `x=4`
and a slant one `y=2x+1`

Explanation:

A vertical asymptote is `x=4` because we cannot divide by `0`
The slant asymptote is `y=2x+1`

graph{(y-2x-1-3/(x-4))(y-2x-1)=0 [-14.24, 14.23, -7.12, 7.12]}