# How do you identify all asymptotes or holes for y=(2x+1)-3/(x-4)?

Nov 1, 2016

There are 2 asymptotes,
a vertical one $x = 4$
and a slant one $y = 2 x + 1$

#### Explanation:

A vertical asymptote is $x = 4$ because we cannot divide by $0$
The slant asymptote is $y = 2 x + 1$

graph{(y-2x-1-3/(x-4))(y-2x-1)=0 [-14.24, 14.23, -7.12, 7.12]}