Question

How do you identify `cot^2x(sin^2x)`?

Answer 1

`cos^2 x`

Explanation:

`cot ^2 x (sin ^2 x) = cos^2 x/cancel(sin^2 x) cancel(sin^2 x) = cos ^2 x`

Answer 2

`cos^2x`

Explanation:

I am assuming you mean `color(blue)"simplify"`

Uing the `color(blue)"trigonometric identity"`

`color(red)(bar(ul(|color(white)(2/2)color(black)(cot^2x=(cos^2x)/(sin^2x))color(white)(2/2)|)))`

`rArrcot^2x(sin^2x)`

`=cos^2x/cancel(sin^2x)^1xxcancel(sin^2x)^1`

`=cos^2x`