How do you identify the important parts of #g(x)= x^2-4x+4# to graph it?

1 Answer
Oct 5, 2015

Intercept: 4
Minimum value: #(2,0)#

Explanation:

From the equation, any number behind #x# is the intercept. So from this equation you know that the intercept is #4#.

Next, complete the square so that the equation is in the form of #a(x+h)^2+k#. This will give you the minimum points of the graph.

If you don't know how to complete a square, it's like this:

  1. Divide the coefficient of #x# by #2#
  2. Take the square out of the #x#, so you will get #(x-2)^2#
  3. Then square the #2# inside the bracket, which gets you #(x-2)^2-4+4#
  4. Finally simplify the equation. #(x-2)^2#

Since there is no number after the brackets, the minimum value of #y# is #0#.

Minimum points= #(2,0)#
(Always switch the negative signs into positive and vice versa for the completed square!)

graph{x^2-4x+4 [-7.19, 8.614, -0.26, 7.64]}