Question

How do you identify the oblique asymptote of `f(x) = (x^2+6x-9)/(x-2)`?

Answer 1

Below

Explanation:

`f(x)=(x^2+6x-9)/(x-2)`

`f(x)=((x-2)(x+8)+7)/(x-2)`

`f(x)=(x+8)+7/(x-2)`

Therefore, the oblique asymptote is `y=x+8` and the vertical asymptote is `x=2`

graph{(x^2+6x-9)/(x-2) [-10, 10, -5, 5]}