How do you identify the value of the discriminant for the equation #6x^2 = 2x – 1#?

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Answer 1 · 2018-03-20T01:16:45

#-20# using Discriminant Formula: #b^2-4ac#

Let's get our quadratic equal to zero first. We can do this from subtracting #6x^2# from both sides. We get:

#-6x^2+2x-1=0#

Our quadratic is in the form #ax^2+bx+c#, where

#a=-6#
#b=2#
#c=-1#

The discriminant of a quadratic is #b^2-4ac#, so we can just plug in these values. We get:

#(2)^2-4(-6)(-1)#

#=>4-4(6)#

#=>4-24=-20#

Therefore, our discriminant is #-20#.