# How do you identify the value of the discriminant for the equation 6x^2 = 2x – 1?

Mar 20, 2018

$- 20$ using Discriminant Formula: ${b}^{2} - 4 a c$

#### Explanation:

Let's get our quadratic equal to zero first. We can do this from subtracting $6 {x}^{2}$ from both sides. We get:

$- 6 {x}^{2} + 2 x - 1 = 0$

Our quadratic is in the form $a {x}^{2} + b x + c$, where

$a = - 6$
$b = 2$
$c = - 1$

The discriminant of a quadratic is ${b}^{2} - 4 a c$, so we can just plug in these values. We get:

${\left(2\right)}^{2} - 4 \left(- 6\right) \left(- 1\right)$

$\implies 4 - 4 \left(6\right)$

$\implies 4 - 24 = - 20$

Therefore, our discriminant is $- 20$.