# How do you implicitly differentiate #-1=sin(x+y) #?

##### 1 Answer

Nov 24, 2016

#### Explanation:

We apply the identity that if

#arcsin(-1) = x + y#

The value of

#d/dx(arcsin(-1)) = d/dx(x + y)#

#0 = 1 + dy/dx#

#dy/dx= -1#

Hopefully this helps!