# How do you integrate 7/(2x-3) using partial fractions?

Feb 25, 2017

You don't need to

#### Explanation:

This is already in a partial fraction form

$\int \frac{7}{2 x - 3} \mathrm{dx}$

$\frac{7}{2} \int \frac{2}{2 x - 3} \mathrm{dx}$

$\frac{7}{2} \ln | 2 x - 3 |$

You only need to use partial fractions when there are multiple (x-k) (or quadratic) terms in the denominator, or the expression is factorable.