How do you integrate # e^(5y)#?

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Nov 2, 2017

Answer:

#e^(5y)/5 + C#

Explanation:

Remember that:
#F(x)=e^x => F'(x)=f(x)=e^x#
And remember the chain rule:
#p(q(x)) => p'(x)= p'(q(x)) q'(x)#

Thus, for: #u(y)=e^(5y)/5 => u'(y) =e^(5y)#
That implies that for: #f(y) = e^(5y) => F(y)=e^(5y)/5 + C#

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