Question

How do you integrate `int cos6x dx`?

Answer 1

`intcos(6x)dx=1/6sin(6x)+C`

Explanation:

Using integration by substitution along with the integral `intcos(x)dx = sin(x)+C`

let `u = 6x => du = 6dx`

then

`intcos(6x)dx = 1/6intcos(6x)6dx`

`=1/6intcos(u)du`

`=1/6sin(u)+C`

`=1/6sin(6x)+C`