How do you integrate #(tanx)^2#?

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14
Aug 21, 2016

Answer:

#tanx-x+C#.

Explanation:

We will use the Trigo. Identity # : sec^2x=tan^2x+1#.

Hence, #int(tanx)^2 dx=int tan^2xdx=int (sec^2x-1)dx#

#=int sec^2xdx-int 1 dx=tanx-x+C#.

Enjoy Maths.!

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