# How do you integrate (x+1)/(x^2+2x+1)?

The answer is: $\ln | x + 1 | + c$.
$y = \frac{x + 1}{x + 1} ^ 2 \Rightarrow y = \frac{1}{x + 1}$,
$\int \frac{1}{x + 1} \mathrm{dx} = \ln | x + 1 | + c$.