How do you integrate # (x + 2)^2 / x^(1/3)#?
1 Answer
Oct 14, 2016
Expand and integrate term by term.
Explanation:
# = x^2/x^(1/3)+(4x)/x^(1/3)+4/x^(1/3)#
# = x^(5/3)+4x^(2/3)+4x^(-1/3) #
# = 3/8x^(8/3)+ 4* 3/5 x^(5/3) +4 (3/2)x^(2/3) +C#
Simplify as desired.