Question

How do you integrate `(x-2)/(x-1)`?

Answer 1

`x - ln(x-1) + C`

Explanation:

`(x-2)/(x-1) = (x-1-1)/(x-1) = 1 - (1)/(x-1)`

`int \ 1 - (1)/(x-1) \ dx = x - ln(x-1) + C`