How do you isolate $r$ in $4(x-3)-r+2x=5(3x-7)-9x$ ?

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Answer 1 · 2016-08-21T14:32:20

$r=23$

$4(x-3)-r+2x=5(3x-7)-9x$

or

$4x-12-r+2x=15x-35-9x$

or

$6x-12=r+6x-35$

or

$r-35=-12$

or

$r=35-12$

or

$r=23$

Answer 2 · 2016-08-21T14:44:07

$r=23$

$4(x-3)-r+2x=5(3x-7)-9x$

$hArr4x-12-r+2x=15x-35-9x$

$hArr6x-12-r=6x-35$

or $cancel(6x)-12-r=cancel(6x)-35$

or $-12-r=-35$ or

$35=12+r$ or

$r=35-12=23$

How do you isolate rr in 4(x-3)-r+2x=5(3x-7)-9x4(x-3)-r+2x=5(3x-7)-9x?