How do you make a the subject in #s=ut+1/2at^2#?

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Answer 1 · 2018-04-07T13:46:56

#a = (2(s-ut))/(t^2)#

#s = ut + 1/2at^2#

subtract #ut# to isolate the term containing #a:#

#s - ut = 1/2at^2#

multiply by #2:#

#2(s-ut) = at^2#

divide by #t^2# to isolate #a:#

#(2(s-ut))/(t^2) = a#

with #a# on the left-hand side,

#a = (2(s-ut))/(t^2)#

or, alternatively (if expanding brackets)

#a = (2s-2ut)/(t^2)#