How do you multiply $-(12-4x)+8(10-x)$ ?

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Answer 1 · 2016-07-09T05:37:52

In this problem, it is easier to distribute the signs first.

$-(12-4x)+8(10-x)$

$=-12+4x+80-8x$

Collecting like terms (the constants and every number with the variable $x$ ) gives us

$-12+80+4x-8x$

$=68-4x$

And since $68$ and $4$ are both divisbly by $4$ , we can simplify further, giving us

$=4(17-x)$

How do you multiply -(12-4x)+8(10-x)-(12-4x)+8(10-x)?