How do you multiply #(2/3x+12)(1/2x-1.2)#?

1 Answer
Jun 13, 2017

Answer:

See a solution process below:

Explanation:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(2/3x) + color(red)(12))(color(blue)(1/2x) - color(blue)(1.2))# becomes:

#(color(red)(2/3x) xx color(blue)(1/2x)) - (color(red)(2/3x) xx color(blue)(1.2)) + (color(red)(12) xx color(blue)(1/2x)) - (color(red)(12) xx color(blue)(1.2))#

#2/6x^2 - 2.4/3x + 6x - 14.4#

#1/3x^2 - 0.8x + 6x - 14.4#

We can now combine like terms:

#1/3x^2 + (-0.8 + 6)x - 14.4#

#1/3x^2 + 5.2x - 14.4#