# How do you multiply ((2, 8), (6, 3)) with ((3, 0), (2, -1))?

Jul 4, 2017

$\left(\begin{matrix}{a}_{11} & {a}_{12} \\ {a}_{21} & {a}_{22}\end{matrix}\right)$

#### Explanation:

The product is $A$.

${a}_{11} = 2 \cdot 3 + 8 \cdot 2$
${a}_{12} = 2 \cdot 0 + 8 \left(- 1\right)$
${a}_{21} = 6 \cdot 3 + 3 \cdot 2$
${a}_{22} = 6 \cdot 0 + 3 \left(- 1\right)$

$A = \left(\begin{matrix}22 & - 8 \\ 24 & - 3\end{matrix}\right)$