How do you multiply #(2x^2-y)(3x^2+y)#?

1 Answer
Don't Memorise
Feb 12, 2016

#=color(blue)(6x^4 -x^2y -y^2#

Explanation:

#color(blue)((2x^2-y))(3x^2+y)#

#=color(blue)((2x^2))(3x^2+y) + color(green)((-y))(3x^2+y)#

#=color(blue)((2x^2))(3x^2) +color(blue)((2x^2))(y) + color(green)((-y))(3x^2) +color(green)((-y)) (y)#

#=6x^4 +2x^2y -3x^2y -y^2#

#=6x^4 -x^2y -y^2#

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