# How do you multiply #(2x-3y)^2#?

##### 1 Answer

The answer is

#### Explanation:

First, we begin by setting it in the form of

#(2x-3y)(2x-3y)#

Using FOIL, we multiply the first term with the outer and inner term of

#4x^2-6xy#

Now we do the same for the last term of the first part so

#-6xy+9y^2#

So we now have the following terms of

#4x^2-6xy-6xy+9y^2#

What we do now is simplify (combine like terms). The final answer is

#4x^2-12xy+9y^2#