How do you multiply #2x ( 4x - 5) ( 3x - 4)#?

1 Answer
smendyka
Nov 29, 2016

#24x^3 - 62x^2 + 40x#

Explanation:

First, cross multiply each term in the first term in parenthesis by each term in the second term in parenthesis:

#2x(12x^2 - 16x - 15x + 20)#

#2x(12x^2 - 31x + 20)#

Then multiply #2x# by each term in the quadratic:

#24x^3 - 62x^2 + 40x#

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