How do you multiply #3 ( x − 7 ) ( x + 2 ) ( 2 x − 1 ) #?

1 Answer
Rafael
Sep 21, 2015

#=6x^3-33x^2-69x+42#

Explanation:

There's really no shortcut to this. You will have to multiply each factor one by one. I suggest you multiply the factor #3# last since that's the easiest. Start with any two from the three binomial factors.

#3(x-7)(x+2)(2x-1)#
#=3(x-7)(2x^2+4x-x-2)#
#=3(x-7)(2x^2+3x-2)#
#=3(2x^3+3x^2-14x^2-2x-21x+14)#
#=3(2x^3-11x^2-23x+14)#

Final Answer
#=6x^3-33x^2-69x+42#

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