How do you multiply #(3g + 8) ( 2g - 4)#?

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Answer 1 · 2017-06-10T22:41:16

See a solution process below:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(3g) + color(red)(8))(color(blue)(2g) - color(blue)(4))# becomes:

#(color(red)(3g) xx color(blue)(2g)) - (color(red)(3g) xx color(blue)(4)) + (color(red)(8) xx color(blue)(2g)) - (color(red)(8) xx color(blue)(4))#

#6g^2 - 12g + 16g - 32#

We can now combine like terms:

#6g^2 + (-12 + 16)g - 32#

#6g^2 + 4g - 32#