How do you multiply (3n-2)(2n+5)? Algebra Polynomials and Factoring Multiplication of Polynomials by Binomials 1 Answer St.Roller Jun 11, 2018 6n^2+11n-10 Explanation: As per the question, we have (3n-2)(2n+5) =(3nxx2n)+(3nxx5)+(-2xx2n)+(-2xx5) =6n^2+15n+(-4n)+(-10) =6n^2+15n-4n-10 =6n^2+11n-10 Hence, the answer. Answer link Related questions What is FOIL? How do you use the distributive property when you multiply polynomials? How do you multiply (x-2)(x+3)? How do you simplify (-4xy)(2x^4 yz^3 -y^4 z^9)? How do you multiply (3m+1)(m-4)(m+5)? How do you find the volume of a prism if the width is x, height is 2x-1 and the length if 3x+4? How do you multiply (a^2+2)(3a^2-4)? How do you simplify (x – 8)(x + 5)? How do you simplify (p-1)^2? How do you simplify (3x+2y)^2? See all questions in Multiplication of Polynomials by Binomials Impact of this question 1656 views around the world You can reuse this answer Creative Commons License