How do you multiply (3n-2)(2n+5)?

Jun 11, 2018

$6 {n}^{2} + 11 n - 10$

Explanation:

As per the question, we have

$\left(3 n - 2\right) \left(2 n + 5\right)$

$= \left(3 n \times 2 n\right) + \left(3 n \times 5\right) + \left(- 2 \times 2 n\right) + \left(- 2 \times 5\right)$

$= 6 {n}^{2} + 15 n + \left(- 4 n\right) + \left(- 10\right)$

$= 6 {n}^{2} + 15 n - 4 n - 10$

$= 6 {n}^{2} + 11 n - 10$