How do you multiply #3sqrt2(sqrt8+5sqrt12)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Don't Memorise Jun 13, 2015 # color(blue)( 12 + 30sqrt6# Explanation: #3sqrt2(sqrt8+5sqrt12)# Multiplying #3sqrt2# with each term within the bracket. # = color(red)((3sqrt2 . sqrt8)) + color(blue)((3sqrt2 . 5sqrt12)# # = color(red)(3.sqrt16) +color(blue)(15.sqrt24)# # = color(red)(3.4) + color(blue)(15.2sqrt6# # = color(blue)( 12 + 30sqrt6# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1342 views around the world You can reuse this answer Creative Commons License