Question

How do you multiply `(3x^2 + 2y)(7x^2 + 3y)`?

Answer 1

`(3x^2 + 2y) (7x^2 + 3y)`

`21x^4 + 9x^2 y+ 14x^2y +6y^2`

`21x^4 + 23x^2y+6y`

Explanation:

Step 1
I multiplied
`3x^2` with `7x^2`
Step 2
I multiplied `3x^2` with `3y`.
So far we have `21x^4 + 9x^2y`
Step 3
I multiplied `2y` with `7x^2`
Step 4
I multiplied `2y` with `3y`.
We have `14x^2y + 6y^2`
Step 5
In total, we have `21x^4+9x^2y+14x^2y+6y^2`
Step 6
We combine like terms. You will see the only like terms are `9x^2y+14x^2y` Those are the only terms we combine.
Final Step
We combine everything
SO our answer is `21x^4+23x^2y+6y^2`