How do you multiply #(3x + 7) ( - 4x - 6)#?

Question

400 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-07-15T17:21:57

See a solution process below:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(3x) + color(red)(7))(-color(blue)(4x) - color(blue)(6))# becomes:

#-(color(red)(3x) xx color(blue)(4x)) - (color(red)(3x) xx color(blue)(6)) - (color(red)(7) xx color(blue)(4x)) - (color(red)(7) xx color(blue)(6))#

#-12x^2 - 18x - 28x - 42#

We can now combine like terms:

#-12x^2 + (-18 - 28)x - 42#

#-12x^2 + (-46)x - 42#

#-12x^2 - 46x - 42#