# How do you multiply 3y ^ { 0} \cdot 2x y ^ { 2}?

Jun 13, 2017

$3 {y}^{0} \cdot 2 x {y}^{2} = 6 x {y}^{2}$

#### Explanation:

Since any number raised to the power $0$ equals $1$

$3 {y}^{0} \cdot 2 x {y}^{2} = 3 \left(1\right) \cdot 2 x {y}^{2}$

And since any number times $1$ is itself

$3 {y}^{0} \cdot 2 x {y}^{2} = 3 \cdot 2 x {y}^{2}$

Then we multiply $2 x {y}^{2}$ by $3$

$3 {y}^{0} \cdot 2 x {y}^{2} = 6 x {y}^{2}$