How do you multiply #(4-2i)^2#?
2 Answers
Sep 30, 2016
Explanation:
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Sep 30, 2016
Explanation:
distribute the brackets using, for example, the FOIL method.
#rArr(4-2i)^2=(4-2i)(4-2i)=16-8i-8i+4i^2#
#color(orange)"Reminder " color(red)(bar(ul(|color(white)(a/a)color(black)(i^2=(sqrt(-1))^2=-1)color(white)(a/a)|)))#
#16-8i-8i+4i^2=16-16i-4#
#rArr(4-2i)^2=12-16i#