# How do you multiply (4+x)(4-x)?

Aug 3, 2016

$16 - {x}^{2}$
$\left(4 + x\right) \left(4 - x\right)$ $=$ $4 \left(4 - x\right) + x \left(4 - x\right)$
$=$ $16 - \cancel{4 x} + \cancel{4 x} - {x}^{2}$
$=$ $- {x}^{2} + 16$