How do you multiply #(6x-4)(7x^2+x-4)#?

1 Answer
Mar 21, 2017

Answer:

#42x^3-22x^2-28x+16#

Explanation:

We must ensure that each term in the second bracket is multiplied by each term in the first bracket. This can be done as follows.

#(color(red)(6x-4))(7x^2+x-4)#

#=color(red)(6x)(7x^2+x-4)color(red)(-4)(7x^2+x-4)#

distribute and simplify.

#=42x^3+6x^2-24x-28x^2-4x+16#

#=42x^3+(6x^2-28x^2)+(-24x-4x)+16#

#=42x^3-22x^2-28x+16#