# How do you multiply (7n+5)(4n+6)?

Apr 28, 2017

$28 {n}^{2} + 62 n + 30$

#### Explanation:

Each term in the second bracket is multiplied by each term in the first bracket as shown below.

$\left(\textcolor{red}{7 n + 5}\right) \left(4 n + 6\right)$

$= \textcolor{red}{7 n} \left(4 n + 6\right) \textcolor{red}{+ 5} \left(4 n + 6\right)$

$= \left(\textcolor{red}{7 n} \times 4 n\right) + \left(\textcolor{red}{7 n} \times 6\right) + \left(\textcolor{red}{5} \times 4 n\right) + \left(\textcolor{red}{5} \times 6\right)$

$= 28 {n}^{2} + 42 n + 20 n + 30$

$= 28 {n}^{2} + 62 n + 30$