How do you multiply #(7x+4)(3x+1)#?

1 Answer
Tony B
Sep 15, 2016

#21x^2+19x+4#

Explanation:

Given:#" "color(blue)((7x+4))color(brown)((3x+1))#

Multiply everything inside the right bracket by everything in the left brackets. Note that the + follows the #color(blue)(+4)#

#color(brown)(color(blue)(7x)(3x+1)" "color(blue)( +4)(3x+1)#

#21x^2+7x" "+12x+4#

#21x^2+19x+4#

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