How do you multiply #(8n + 4) ( 2n + 6)#?

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Answer 1 · 2018-02-25T12:31:16

#16n^2+56n+24#

You would multiply each term in both brackets. Most people use FOIL, which stands for first, outer, inner and last.

Eg,

#(color(red)(8n)+color(green)(4))(color(blue)(2n)+color(cyan)(6))#

#color(red)(8n)xxcolor(blue)(2n)=color(red)(16n^2#

#color(red)(8n)xxcolor(cyan)(6)=color(Blue)(48n#

#color(green)(4)xxcolor(blue)(2n)=color(blue)(8n#

#color(green)(4)xxcolor(cyan)(6)=color(green)(24#

Collecting like-terms:

#color(red)(16n^2)+color(blue)(48n+8n)+color(green)(24)#

#=color(red)(16n^2)+color(blue)(56n)+color(green)(24)#

#therefore# The answer is #16n^2+56n+24#