How do you multiply #\frac { y ^ { 2} - 2y + 1} { y ^ { 2} - 1} \cdot \frac { 2y ^ { 2} + y - 1} { 5y - 5}#?

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Answer 1 · 2016-11-17T21:22:48

#((2y-1))/5#

You are multiplying algebraic fractions:

#(y^2-2y+1)/(y^2-1) xx(2y^2+y-1)/(5y-5)#

Try to find factors wherever possible:

#"quadratic trinomial"/"difference of squares" xx "quadratic trinomial"/"common factor"#

=#((y-1)(y-1))/((y+1)(y-1)) xx ((y+1)(2y-1))/(5(y-1))#

Now cancel like factors

=#(cancel((y-1))cancel((y-1)))/(cancel((y+1))cancel((y-1))) xx (cancel((y+1))(2y-1))/(5cancel((y-1)))#

=#((2y-1))/5#

#"top x top"/"bottom x bottom"#