How do you multiply #(p + 4) ( p - 15)#?

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Answer 1 · 2017-05-25T01:03:46

See a solution process below:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(p) + color(red)(4))(color(blue)(p) - color(blue)(15))# becomes:

#(color(red)(p) xx color(blue)(p)) - (color(red)(p) xx color(blue)(15)) + (color(red)(4) xx color(blue)(p)) - (color(red)(4) xx color(blue)(15))#

#p^2 - 15p + 4p - 60#

We can now combine like terms:

#p^2 + (-15 + 4)p - 60#

#p^2 + (-11)p - 60#

#p^2 - 11p - 60#